Các câu hỏi tương tự
Cho biểu thức A = \(\left(\dfrac{\sqrt{ab}+\sqrt{b}}{\sqrt{a}+\sqrt{b}}+\dfrac{\sqrt{ab}+\sqrt{a}}{\sqrt{b}-\sqrt{a}}+1\right):\left(\dfrac{\sqrt{ab}+\sqrt{b}}{\sqrt{a}+\sqrt{b}}+\dfrac{\sqrt{ab}+\sqrt{a}}{\sqrt{a}-\sqrt{b}}-1\right)\)
Cho \(\sqrt{ab}+1=4.\sqrt{b}\), tìm max của biểu thức A.
15 tháng 12 2019 lúc 12:19
CHo ba số a , b , c không âm đôi một khác nhau . Chứng minh rằng :
\(\frac{\sqrt{a}+\sqrt{b}}{\sqrt{a}-\sqrt{b}}.\frac{\sqrt{b}+\sqrt{c}}{\sqrt{b}-\sqrt{c}}.+\frac{\sqrt{b}+\sqrt{c}}{\sqrt{b}-\sqrt{c}}.\frac{\sqrt{c}+\sqrt{a}}{\sqrt{c}-\sqrt{a}}+\frac{\sqrt{c}+\sqrt{a}}{\sqrt{c}-\sqrt{a}}.\frac{\sqrt{a}+\sqrt{b}}{\sqrt{a}-\sqrt{b}}=-1\) .
22 tháng 3 2022 lúc 8:36
Thực hiện các phép tính :
1. \(A=\sqrt{2-\sqrt{3}}\sqrt{2+\sqrt{2-\sqrt{3}}}\sqrt{2+\sqrt{2+\sqrt{2-\sqrt{3}}}}\sqrt{2+\sqrt{2+\sqrt{2+\sqrt{2-\sqrt{3}}}}}\)
2. \(B=\left(\dfrac{1}{1+\sqrt{2}}+\dfrac{2}{2+\sqrt{3}}+...+\dfrac{1}{20+\sqrt{21}}\right)\cdot2022\)
Giải chi tiết giúp mình ạ
Chứng minh các đẳng thức sau: a) left(1-a^2right):left[left(frac{1-asqrt{a}}{1-sqrt{a}}+sqrt{a}right)left(frac{1
+asqrt{a}}{1+sqrt{a}}-sqrt{a}right)right]+1frac{2}{1-a}b) left(sqrt{a}+frac{b-sqrt{ab}}{sqrt{a}+sqrt{b}}right):left(frac{a}{sqrt{ab}+b}
+frac{b}{sqrt{ab}-a}-frac{a+b}{sqrt{ab}}right)sqrt{b}-sqrt{a}c) frac{sqrt{a}+sqrt{b}-1}{a
+sqrt{ab}}+frac{sqrt{a}-sqrt{b}}{2sqrt{ab}}left(frac{sqrt{b}}{a-sqrt{ab}}+frac{sqrt{b}}{a
+sqrt{ab}}right)frac{sqrt{a}}{a}d) left(frac{asqrt{a}+bsqrt{b}}{sqrt{a}...
Đọc tiếp
Chứng minh các đẳng thức sau:
a) \(\left(1-a^2\right):\left[\left(\frac{1-a\sqrt{a}}{1-\sqrt{a}}+\sqrt{a}\right)\left(\frac{1
+a\sqrt{a}}{1+\sqrt{a}}-\sqrt{a}\right)\right]+1=\frac{2}{1-a}\)
b) \(\left(\sqrt{a}+\frac{b-\sqrt{ab}}{\sqrt{a}+\sqrt{b}}\right):\left(\frac{a}{\sqrt{ab}+b}
+\frac{b}{\sqrt{ab}-a}-\frac{a+b}{\sqrt{ab}}\right)=\sqrt{b}-\sqrt{a}\)
c) \(\frac{\sqrt{a}+\sqrt{b}-1}{a
+\sqrt{ab}}+\frac{\sqrt{a}-\sqrt{b}}{2\sqrt{ab}}\left(\frac{\sqrt{b}}{a-\sqrt{ab}}+\frac{\sqrt{b}}{a
+\sqrt{ab}}\right)=\frac{\sqrt{a}}{a}\)
d) \(\left(\frac{a\sqrt{a}+b\sqrt{b}}{\sqrt{a}+\sqrt{b}}-\sqrt{ab}\right)\left(\frac{\sqrt{a}+\sqrt{b}}{a-b}\right)^2=1\)
rút gọn các căn thức sauBfrac{sqrt{5-sqrt{3}}-sqrt{5+sqrt{3}}}{sqrt{5-sqrt{22}}}+sqrt{27+10sqrt{2}}C frac{sqrt{45+27sqrt{2}}+sqrt{45-27sqrt{2}}}{sqrt{5+3sqrt{2}}-sqrt{5-3sqrt{2}}}-frac{sqrt{3+sqrt{2}}+sqrt{3-sqrt{2}}}{sqrt{3+sqrt{2}}-sqrt{3-sqrt{2}}}Dfrac{1}{sqrt{2}-sqrt{3}}.sqrt{frac{3sqrt{2}-2sqrt{3}}{3sqrt{2}+2sqrt{3}}}A frac{1}{sqrt{3+2sqrt{2}}}+frac{1}{sqrt{5+2sqrt{6}}}+frac{1}{sqrt{7+2sqrt{12}}}+....+frac{1}{sqrt{199+2sqrt{9900}}}
Đọc tiếp
rút gọn các căn thức sau
B=\(\frac{\sqrt{5-\sqrt{3}}-\sqrt{5+\sqrt{3}}}{\sqrt{5-\sqrt{22}}}+\sqrt{27+10\sqrt{2}}\)C= \(\frac{\sqrt{45+27\sqrt{2}}+\sqrt{45-27\sqrt{2}}}{\sqrt{5+3\sqrt{2}}-\sqrt{5-3\sqrt{2}}}-\frac{\sqrt{3+\sqrt{2}}+\sqrt{3-\sqrt{2}}}{\sqrt{3+\sqrt{2}}-\sqrt{3-\sqrt{2}}}\)D=\(\frac{1}{\sqrt{2}-\sqrt{3}}.\sqrt{\frac{3\sqrt{2}-2\sqrt{3}}{3\sqrt{2}+2\sqrt{3}}}\)A= \(\frac{1}{\sqrt{3+2\sqrt{2}}}+\frac{1}{\sqrt{5+2\sqrt{6}}}+\frac{1}{\sqrt{7+2\sqrt{12}}}+....+\frac{1}{\sqrt{199+2\sqrt{9900}}}\)
a : \(\sqrt{2-\sqrt{3}}+\sqrt{2+\sqrt{3}}\)
b : \(\sqrt{4-\sqrt{7}}-\sqrt{4+\sqrt{7}}\)
c : \(\sqrt{\left(2\sqrt{5}+1\right)^2}-\sqrt{\left(\sqrt{5}-2\right)^2}\)
d : \(\sqrt{52-16\sqrt{3}}+\sqrt{\left(4\sqrt{3}-7\right)^2}\)
thực hiện phép tính: a)left(frac{sqrt{14}-sqrt{7}}{1-sqrt{2}}+frac{sqrt{15}+sqrt{5}}{1-sqrt{3}}right):frac{1}{sqrt{7}-sqrt{5}}b)frac{sqrt{5}-sqrt{3}}{sqrt{5}+sqrt{3}}+frac{sqrt{5}+sqrt{3}}{sqrt{5}-sqrt{3}}+frac{sqrt{5}+1}{sqrt{5}-1}c)2sqrt{18sqrt{3}}-2sqrt{5sqrt{3}}-3sqrt{5sqrt{48}}d)left(2sqrt{5}+sqrt{12}right)left(sqrt{3}-sqrt{5}right)e)sqrt{2}+sqrt{frac{1}{2}}+sqrt{72}-sqrt{frac{3}{2}}f)sqrt{2}sqrt{2+sqrt{3}}-2left(sqrt{3}-1right)g)sqrt{5-2sqrt{6}}+sqrt{5+2sqrt{6}}-left(2sqrt{3}-2007right)
Đọc tiếp
thực hiện phép tính: a)\(\left(\frac{\sqrt{14}-\sqrt{7}}{1-\sqrt{2}}+\frac{\sqrt{15}+\sqrt{5}}{1-\sqrt{3}}\right):\frac{1}{\sqrt{7}-\sqrt{5}}\)
b)\(\frac{\sqrt{5}-\sqrt{3}}{\sqrt{5}+\sqrt{3}}+\frac{\sqrt{5}+\sqrt{3}}{\sqrt{5}-\sqrt{3}}+\frac{\sqrt{5}+1}{\sqrt{5}-1}\)
c)\(2\sqrt{18\sqrt{3}}-2\sqrt{5\sqrt{3}}-3\sqrt{5\sqrt{48}}\)
d)\(\left(2\sqrt{5}+\sqrt{12}\right)\left(\sqrt{3}-\sqrt{5}\right)\)
e)\(\sqrt{2}+\sqrt{\frac{1}{2}}+\sqrt{72}-\sqrt{\frac{3}{2}}\)
f)\(\sqrt{2}\sqrt{2+\sqrt{3}}-2\left(\sqrt{3}-1\right)\)
g)\(\sqrt{5-2\sqrt{6}}+\sqrt{5+2\sqrt{6}}-\left(2\sqrt{3}-2007\right)\)
a) A=\(\sqrt{\left(4-\sqrt{15}\right)^2+\sqrt{15}}\)
b) B=\(\sqrt{\left(2-\sqrt{3}\right)^2}+\sqrt{\left(1-\sqrt{3}\right)^2}\)
c) C=\(\sqrt{49-12\sqrt{5}}-\sqrt{49+12\sqrt{5}}\)
d)D=\(\sqrt{29+12\sqrt{5}-\sqrt{29-12\sqrt{5}}}\)
Tính
a)\(\frac{1}{\sqrt{2}+\sqrt{1}}+\frac{1}{\sqrt{3}+\sqrt{2}}+\frac{1}{\sqrt{4}+\sqrt{3}}+....+\frac{1}{\sqrt{1936}+\sqrt{1935}}\)
b)\(\frac{1}{\sqrt{1}-\sqrt{1}}-\frac{1}{\sqrt{2}-\sqrt{3}}+\frac{1}{\sqrt{3}+\sqrt{4}}-\frac{1}{\sqrt{4}+\sqrt{5}}+....-\frac{1}{\sqrt{8}-\sqrt{2}}\)