Question

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Answer 1

\(\left\{{}\begin{matrix}\dfrac{2}{x}+\dfrac{1}{y}=2\\\dfrac{6}{x}-\dfrac{2}{y}=1\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}\dfrac{4}{x}+\dfrac{2}{y}=4\\\dfrac{6}{x}-\dfrac{2}{y}=1\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}\dfrac{10}{x}=5\\\dfrac{2}{x}+\dfrac{1}{y}=2\end{matrix}\right.\)