Question

Ai giải giúp mình với

Answer 1

Bài 10.

\(\dfrac{1}{R_{tđ}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}=\dfrac{1}{150}=\dfrac{1}{330}+\dfrac{1}{R_2}\)

\(\Rightarrow R_2=275\Omega\)

Answer 2

Bài 11:

\(100mA=0,1A\)

Ta có: \(U=U1=U2=IR=0,1\cdot\left(100+47\right)=14,7V\left(R1//R2\right)\)

\(\Rightarrow\left\{{}\begin{matrix}I1=U1:R1=14,7:100=0,147A\\I2=U2:R2=14,7:47=\dfrac{147}{470}A\end{matrix}\right.\)