\(\dfrac{3}{8}+\dfrac{1}{4}=\dfrac{3}{8}+\dfrac{2}{8}=\dfrac{5}{8}\)
\(\dfrac{-4}{15}+\dfrac{2}{5}=\dfrac{-4}{15}+\dfrac{6}{15}=\dfrac{2}{15}\)
\(\text{a},=\dfrac{3+1.2}{8}=\dfrac{5}{8}\\ b,=\dfrac{-4+2.3}{15}=\dfrac{2}{15}\)
\(a,\dfrac{3}{8}+\dfrac{1}{4}=\dfrac{3+2}{8}=\dfrac{5}{8}.\)
\(b,\dfrac{-4}{15}+\dfrac{2}{5}=\dfrac{2}{5}-\dfrac{4}{15}=\dfrac{6-4}{15}=\dfrac{2}{15}.\)