Question

 a)\(\dfrac{3x}{2}+\dfrac{4x-3}{10}-\dfrac{15x-1}{5}\)

 b)\(\dfrac{x-4}{x+1}+\dfrac{x+1}{x}=2\)

Answer 1

a: \(=\dfrac{5\cdot3x+4x-3-2\left(15x-1\right)}{10}=\dfrac{19x-3-30x+2}{10}=\dfrac{-11x-1}{10}\)

b: \(\Leftrightarrow x\left(x-4\right)+\left(x+1\right)^2=2x\left(x+1\right)\)

\(\Leftrightarrow x^2-4x+x^2+2x+1=2x^2+2x\)

=>-2x+1=2x

=>-4x=-1

hay x=1/4(nhận)

Answer 2

\(a,\dfrac{3x}{2}+\dfrac{4x-3}{10}-\dfrac{15x-1}{5}\)

\(=\dfrac{3x.5+4x-3-2\left(15x-1\right)}{10}\)

\(=\dfrac{15x+4x-3-30x+3}{10}\)

\(=\dfrac{-11x}{10}\)