\(a,\dfrac{1}{2}x\dfrac{1}{3}-\dfrac{1}{8}=\dfrac{1}{6}-\dfrac{1}{8}=\dfrac{8}{48}-\dfrac{6}{48}=\dfrac{2}{48}=\dfrac{1}{24}\)
\(b,\dfrac{5}{2}:\dfrac{1}{4}-\dfrac{1}{8}=10-\dfrac{1}{8}=\dfrac{10}{1}-\dfrac{1}{8}=\dfrac{80}{8}-\dfrac{1}{8}=\dfrac{79}{8}\)
a,\(\left(\dfrac{1}{2}\times\dfrac{1}{3}\right)-\dfrac{1}{8}=\dfrac{1}{6}-\dfrac{1}{8}=\dfrac{8}{48}-\dfrac{6}{48}=\dfrac{2}{48}=\dfrac{1}{24}\)
b,\(\left(\dfrac{5}{2}:\dfrac{1}{4}\right)-\dfrac{1}{8}=\left(\dfrac{5}{2}\times\dfrac{4}{1}\right)-\dfrac{1}{8}=\dfrac{20}{2}-\dfrac{1}{8}=10-\dfrac{1}{8}=\dfrac{10}{1}-\dfrac{1}{8}=\dfrac{80}{8}-\dfrac{1}{8}=\dfrac{79}{8}\)