\(ab+ba=165\)
\(a0+b+b0+a=165\)
\(aa+bb=165\)
\(\left(a+b\right)\cdot11=165\)
\(a+b=165\) \(\text{:}\) \(11\)
\(a+b=15\)
ab + ba = 165
10×a + b + 10×b + a = 165
11×a + 11×b = 165
11×(a + b) = 165
a + b = 165 : 11
a + b = 15
ab + ba = 165
10×a + b + 10×b + a = 165
11×a + 11×b = 165
11×(a + b) = 165
a + b = 165 : 11
a + b = 15