Question

a, \(\dfrac{2}{3}\) - \(\dfrac{4}{7}\) : \(\dfrac{9}{14}\)

b, x - \(\dfrac{7}{3}\) = \(\dfrac{8}{9}\)

c, \(\dfrac{3}{4}\) x + \(\dfrac{1}{4}\) ( x + 1 ) = - \(\dfrac{11}{4}\)

Answer 1

a: \(\dfrac{2}{3}-\dfrac{4}{7}:\dfrac{9}{14}\)

\(=\dfrac{2}{3}-\dfrac{4}{7}\cdot\dfrac{14}{9}\)

\(=\dfrac{2}{3}-\dfrac{8}{9}=\dfrac{6}{9}-\dfrac{8}{9}=-\dfrac{2}{9}\)

b: \(x-\dfrac{7}{3}=\dfrac{8}{9}\)

=>\(x=\dfrac{8}{9}+\dfrac{7}{3}=\dfrac{8}{9}+\dfrac{21}{9}=\dfrac{30}{9}=\dfrac{10}{3}\)

c: \(\dfrac{3}{4}x+\dfrac{1}{4}\left(x+1\right)=-\dfrac{11}{4}\)

=>\(\dfrac{3}{4}x+\dfrac{1}{4}x+\dfrac{1}{4}=-\dfrac{11}{4}\)

=>\(x=-\dfrac{11}{4}-\dfrac{1}{4}=-\dfrac{12}{4}=-3\)