\(=\dfrac{5}{18}-\dfrac{5}{6}+\dfrac{7}{3}=\dfrac{16}{9}\)
= \(\dfrac{5}{18}\)+ \(\dfrac{5}{6}\)+\(\dfrac{7}{3}\)
=\(\dfrac{5+3.5+7.6}{18}\)
=\(\dfrac{31}{9}\)
\(=\dfrac{5}{18}-\dfrac{5}{6}+\dfrac{7}{3}=\dfrac{16}{9}\)
= \(\dfrac{5}{18}\)+ \(\dfrac{5}{6}\)+\(\dfrac{7}{3}\)
=\(\dfrac{5+3.5+7.6}{18}\)
=\(\dfrac{31}{9}\)
Giúp mình với ạ, giải chi tiết nhé !
Mình xin cảm ơn !
a/ \(\sqrt{25}\) - 3\(\sqrt{\dfrac{4}{9}}\)
b/ (2 - \(\dfrac{5}{3}\)) : (\(\dfrac{2}{7}\) + \(\dfrac{5}{21}\) - 1)
c/ 12,7 - 17,2 + 199,9 - 22,8 - 149,9
d/ (\(\dfrac{-1}{2}\))4 + |\(\dfrac{-2}{3}\)| - 20070
e/ 4(\(\dfrac{-1}{2}\))3 + |\(\dfrac{1}{2}\)| : 5
g/ 3 - (\(\dfrac{-6}{7}\))0 + \(\sqrt{9}\) : 2
h/ \(\dfrac{27}{23}\) + \(\dfrac{5}{21}\) - \(\dfrac{4}{23}\) + \(\dfrac{6}{21}\) + \(\dfrac{1}{2}\)
a) | \(\dfrac{-11}{6}\) | + ( \(\dfrac{-14}{3}\) ) + \(\sqrt{\dfrac{16}{8}}\)
Giúp em với ạ , Many Thanks !!!
Giúp mình với ạ, mình xin cảm ơn trước ạ !.
\(\dfrac{5}{21}\) + \(\dfrac{1}{2}\) - \(\dfrac{19}{23}\) + \(\dfrac{16}{21}\) - \(\dfrac{4}{23}\)
a,(0,8)5:(0,4)6 b, (-25)7:323 c, \(\dfrac{4^2.4^3}{2^{10}}\) d,\(\dfrac{9^5.5^7}{45^7}\)
Giúp em với ạ e cảm ơn nhiều ạ!
a,-12:(3/4-5/6)^2
,b,10.\(\sqrt{0.01}.\sqrt{\dfrac{16}{9}+3\sqrt{49}-\dfrac{1}{6}\sqrt{4}}\)
c,x/6=y/3=z/2 và x-2y+4z=8
d,|1/4+x|-1/3=2/5
so sánh các số sau : \(a=\dfrac{35}{49};b=\sqrt{\dfrac{5^2}{7^2}};c=\dfrac{\sqrt{5^2}+\sqrt{35^2}}{\sqrt{7^2}+\sqrt{49^2}};d=\dfrac{\sqrt{5^2}-\sqrt{35^2}}{\sqrt{7^2}-\sqrt{49^2}}\)
Thực hiện phép tính:
\(A=\dfrac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}-\dfrac{5^{10}.7^3-25^5.49^2}{\left(125.7\right)^3+5^9.14^3}\)
\(B=\dfrac{1-\dfrac{1}{\sqrt{49}}+\dfrac{1}{49}-\dfrac{1}{\left(7\sqrt{7}\right)^2}}{\dfrac{\sqrt{64}}{2}-\dfrac{4}{7}+\dfrac{2^2}{7^2}-\dfrac{4}{343}}\)
\(\dfrac{x}{4}\)=\(\dfrac{5}{4}\)\(và\)\(x+y=18\)
\(Giúp\) \(mik\) \(vs\)\(mik\) \(đg\) \(cần\) \(gấp\) \(ạ\).
\(\sqrt{\dfrac{16}{49}}+\left(\dfrac{1}{2}\right)^3-\left|-\dfrac{4}{7}\right|-\dfrac{7}{8}\)
\(\left|\dfrac{1}{2}-\dfrac{3}{5}\right|\cdot\sqrt{9}+0.5\cdot\left(-2\dfrac{3}{5}\right)\)
Bài 2:Thực hiện phép tính
a)-12:(\(\dfrac{3}{4}\)-\(\dfrac{5}{6}\))\(^2\)
b) (2\(^2\):\(\dfrac{4}{3}\)-\(\dfrac{1}{2}\)).\(\dfrac{6}{5}\)-17
Giúp vs ạ cần gấp