a: \(\dfrac{-5}{9}+\dfrac{4}{-9}=\dfrac{-5}{9}+\dfrac{-4}{9}=\dfrac{-5-4}{9}=\dfrac{-9}{9}=-1\)
b: \(\dfrac{-5}{39}-\left(\dfrac{34}{39}+\dfrac{5}{-3}\right)\)
\(=\dfrac{-5}{39}-\dfrac{34}{39}+\dfrac{5}{3}\)
\(=-\dfrac{39}{39}+\dfrac{5}{3}=-1+\dfrac{5}{3}=\dfrac{2}{3}\)
Lời giải:
a. $\frac{-5}{9}+\frac{4}{-9}=\frac{-5}{9}+\frac{-4}{9}=\frac{-9}{9}=-1$
b. $\frac{-5}{39}-(\frac{34}{39}+\frac{5}{-3})=\frac{-5}{39}-\frac{34}{39}+\frac{5}{3}$
$=\frac{-39}{39}+\frac{5}{3}=-1+\frac{5}{3}=\frac{2}{3}$