Question

a) 3x²- 3y²-12x+12y

Answer 1

\(=3\left(x^2-y^2\right)-12\left(x-y\right)=3\left(x-y\right)\left(x+y\right)-12\left(x-y\right)=3\left(x-y\right)\left(x+y-4\right)\)

Answer 2

\(3x^2-3y^2-12x+12y\)

\(=3\left(x^2-y^2\right)-12\left(x-y\right)\)

\(=3\left(x-y\right)\left(x+y\right)-12\left(x-y\right)\)

\(=\left(x-y\right)\left[3\left(x+y\right)-12\right]\)

\(=\left(x-y\right)\left(3x+3y-12\right)\)

\(=3\left(x-y\right)\left(x+y-4\right)\)