`0,5.x - 2/3.(x+1) = -1/12`
`=> 1/2.x - 2/3 . x - 2/3 = -1/12`
`=> (1/2 - 2/3) . x = -1/12+ 2/3`
`=> -1/6 . x = 7/12`
`=> x = 7/12 : (-1/6)`
`=> x = -7/2`
Vậy `x=-7/2`
\(0,5x-\dfrac{2}{3}\left(x+1\right)=-\dfrac{1}{12}\)
=>\(\dfrac{1}{2}x-\dfrac{2}{3}x-\dfrac{2}{3}=-\dfrac{1}{12}\)
=>\(-\dfrac{1}{6}x=-\dfrac{1}{12}+\dfrac{2}{3}=\dfrac{8}{12}-\dfrac{1}{12}=\dfrac{7}{12}\)
=>\(x=\dfrac{7}{12}:\dfrac{-1}{6}=\dfrac{7}{12}\cdot\left(-6\right)=-\dfrac{7}{2}\)