\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-3\\x=2\end{matrix}\right.\)
\(\Leftrightarrow3\left(x-2\right)\left(3-x\right)\left(3+x\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=3\\x=-3\\x=2\end{matrix}\right.\)
\(\Leftrightarrow\)\(\left[{}\begin{matrix}x=3\\x=-3\\x=2\end{matrix}\right.\)
@Lâm
TH1: 9-x2 =0
x2=9-0=9
x=9:2=4,5
TH2: 3x-6=0
3x=0+6=6
x=6:3=2