`@` `\text {Ans}`
`\downarrow`
`8x - 5x = 1011`
`\Rightarrow (8 - 5)x = 1011`
`\Rightarrow 3x = 1011`
`\Rightarrow x = 1011 \div 3`
`\Rightarrow x = 337`
Vậy, `x = 337.`
8x - 5x = 1011
3x = 1011
x = 1011 :3
x = 337
8x-5x=1011
=>x(8-5)=1011
=>3x=1011
=>x=1011:3=337
Vậy x=337.
\(8x-5x=1011\)
\(3x=1011\)
\(x=1011:3\)
\(x=337\)
3x=1011
x=1011:3
x=337
vậy x=337 nha
\(\Rightarrow\left(8-5\right)x=1011\Rightarrow3x=1011\Rightarrow x=1011:3\Rightarrow x=337\)