\(\Leftrightarrow\left[{}\begin{matrix}8-x=0\\x +5=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=8\\x=-5\end{matrix}\right.\)
\(x\in\left\{8;-5\right\}\)
=> 8-x=0 hoặc x+5=0
TH1 TH2
8-x=0 x+5=0
x=0+8 x =0-5
x=8 x =-5
\(\left(8-x\right)\left(x+5\right)\Leftrightarrow\left[{}\begin{matrix}8-x=0\\x+5=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}8\\-5\end{matrix}\right.\)