Question

|8-x|=x² + x

Answer 1

TH1: `8-x>=0 <=>x<=8`

`8-x=x^2+x`

`x^2+2x-8=0`

`[(x=2(TM)),(x=-4(TM)):}

TH2: `x>8`

`x-8=x^2+x`

`x^2=-8`(VN)
Vậy `x=2;x=-4`.

Answer 2

Ta có:

8-x=\(x^2\)+x hay x-8 = \(x^2\)+x

=> 8 = \(x^2\) +x hay -8 = \(x^2\)

=> \(x^2\) +x-8 = 0 hay x vô nghiệm

=> x= (-1+\(\sqrt{33}\))/2 hay (-1 - \(\sqrt{33}\))/2

đúng thì like giúp mik nha bạn. Thx bạn

 

\(x^2\)