\(\dfrac{7x-26}{x-1}=\dfrac{2}{3}đkxđ\left(x\ne1\right)\\ \Leftrightarrow\dfrac{3\left(7x-26\right)}{3\left(x-1\right)}=\dfrac{2\left(x-1\right)}{3\left(x-1\right)}\\ \Rightarrow3\left(7x-26\right)=2\left(x-1\right)\\ \Leftrightarrow21x-78=2x-2\\ \Leftrightarrow21x-2x=-2+78\\ \Leftrightarrow19x=76\\ \Leftrightarrow x=4\)
Vậy pt có nghiệm `x=4`
(x+1)^3 + x(x^2+5x)-x(8x-10)+7x=1-4x.26+29
tìm x
Phân tích đa thức thành nhân tử:
1, x^3-x+y^3-4
2, 4x^2-y^2+4x+1
3, x^4+2x^3+x^2
4, x^2+5x-6
5, 7x-6x^2-2
6, 5x^2+5xy-x-y
7, 2x^2+3x-5
8,x^4-5x^2+4
9, x^3-5x^2+45-9x
10, x^4-2x^3-2x^2-2x-3
11, 81x^4+4
12,x^5+x+1
13, x^4+6x^3+7x^2-6x+1
14, x(x+4)(x+6)(x+10)+128
Tìm x
a,x^2-11x-26=0
b,2x^2+7x-4=0
c,(x-2)(x-3)+(x-2)-1=0
HELP ME TÍ NX ĐI HK R
2x3+11x2+3x-26
x3-5x2+2x+8
3x3+5x2-x-2
6x3-7x2+5x-2
giải các phương trình
a) (3x-2)(3x-1) = (3x+1)2
b) (4x-1)(x+1) = (2x-3)2
c) (5x+1)2 = (7x-3)(7x+2)
d) (4-3x)(4+3x)=(9x-3)(1-x)
e) x(x+1)(x+2)(x+3)=24
g) (7x - 2)2= (7x-3)(7x+2)
Tìm x,y:
a)3x(2x-12+7x(3y+5)2=0
b)x2+y2-2x+10y+26=0
tìm x : (7x+3)2-(7x-1)(7x-3)=-12
Rút gọn
A. ( x -5 ) ( 7x +1 ) - 7x ( x+3)
B. ( x-2)2 - ( x-1) ( x+1)
