\(7^{2x}+7^{2x+3}=344\\\Rightarrow7^{2x}+7^{2x}\cdot7^3=344\\\Rightarrow7^{2x}\cdot(1+7^3)=344\\\Rightarrow7^{2x}\cdot(1+343)=344\\\Rightarrow7^{2x}\cdot344=344\\\Rightarrow7^{2x}=1\\\Rightarrow2x=0\\\Rightarrow x=0\)
\(7^{2x}+7^{2x+3}=344\\\Rightarrow7^{2x}+7^{2x}\cdot7^3=344\\\Rightarrow7^{2x}\cdot(1+7^3)=344\\\Rightarrow7^{2x}\cdot(1+343)=344\\\Rightarrow7^{2x}\cdot344=344\\\Rightarrow7^{2x}=1\\\Rightarrow2x=0\\\Rightarrow x=0\)
\(7^{2x}+7^{2x+3}=344\)
\(7^{2x}+7^{2x}.7^3=344\)
tìm x biết
a)1/6+x=5/12
b3/4+1/4x=-1/2
c)7 mũ 2x +7 mũ 2x +3=344
\(7^{2x}+7^{2x+3}=344\)
Giúp mik vs
mink cần gấp
Tìm x biết
7x + 72x+3 = 344
Muốn đc tick hơm -_- , vô đây cho zui
\(7^x+7^{2x+3}=344\)
7^x + 7^x+3 = 344
mk làm đen :
7^x * 1 + 7^x * 7^3 = 344
7^x ( 1 + 7^3 ) = 344
7 ^x * ( 1+343 ) = 344
7^x * 344 = 344
7 ^x = 344 : 344
7 ^x = 1
k bt làm nx
- giúp mk vs ạ
\(\dfrac{7^{x+2}+7^{x+1}+7^x}{57}=\dfrac{5^{2x}+5^{2x+1}+5^{2x+3}}{131}\)
a) 5(x-2)(x+3)=1
b) 7(x-2024)2 = 23- y2
c) |x2+ 2x| + |y2- 9|= 0
d) 2x+ 2x+1+2x+2+2x+3=120
e) ( x- 7 )x+1- (x - 7)x+11=0
f) 25 - y2= 8(x 2012)2