\(\dfrac{6}{7}=1-\dfrac{1}{7}\)
\(\dfrac{5}{6}=1-\dfrac{1}{6}\)
\(\dfrac{7}{8}=1-\dfrac{1}{8}\)
\(\dfrac{9}{10}=1-\dfrac{1}{10}\)
\(\dfrac{8}{9}=1-\dfrac{1}{9}\)
Do \(\dfrac{1}{10}< \dfrac{1}{9}< \dfrac{1}{8}< \dfrac{1}{7}< \dfrac{1}{6}\)
\(\Rightarrow1-\dfrac{1}{6}< 1-\dfrac{1}{7}< 1-\dfrac{1}{8}< 1-\dfrac{1}{9}< 1-\dfrac{1}{10}\)
\(\Rightarrow\dfrac{5}{6}< \dfrac{6}{7}< \dfrac{7}{8}< \dfrac{8}{9}< \dfrac{9}{10}\)
6/7=1-1/7
5/6=1-1/6
7/8=1-1/8
9/10=1-1/10
8/9=1-1/9
mà 1/6>1/7>1/8>1/9>1/10
nên 5/6<6/7<7/8<8/9<9/10