Question

5x(x-2)-10x+20=0

Answer 1

\(PT< =>5x\left(x-2\right)-10\left(x-2\right)=0\)

\(< =>\left(x-2\right)\left(5x-10\right)=0\)

\(< =>\left[{}\begin{matrix}x-2=0\\5x-10=0\end{matrix}\right.\)

\(< =>x=2\)

Answer 2

`5x(x-2)-10x+20=0`

`=>5x(x-2)-10(x-2)=0`

`=>(5x-10)(x-2)=0`

`=>5x-10=0` hoặc `x-2=0`

`=>5x=10` hoặc `x=0+2`

`=>x=2`

Vậy `x=2`