Question

\(5\left(x^2-2x-1\right)+2\left(3x-2\right)=5\left(x+1\right)\)

Answer 1

Ghi nhầm đề bài =="

`5(x^2-2x-1)+2(3x-2)=5(x+1)`

`<=>5x^2-10x-5+6x-4=5x+5`

`<=>5x^2-4x-9=5x+5`

`<=>5x^2-9x-14=0`

`<=>5x^2+5x-14x-14=0`

`<=>5x(x+1)-14(x+1)=0`

`<=>(x+1)(5x-14)=0`

`<=>` \(\left[ \begin{array}{l}x=\dfrac{14}{5}\\x=-1\end{array} \right.\) 

Vậy `S={-1,,14/5}`