\(\left(\dfrac{5}{6}+\dfrac{7}{x}\right)-\dfrac{16}{12}=\dfrac{2}{3}\)
\(\Rightarrow\dfrac{5}{6}+\dfrac{7}{x}=\dfrac{2}{3}+\dfrac{16}{12}=\dfrac{8}{12}+\dfrac{16}{12}=\dfrac{24}{12}=2\)
\(\Rightarrow\dfrac{7}{x}=2-\dfrac{5}{6}=\dfrac{12}{6}-\dfrac{5}{6}=\dfrac{7}{6}\)
=> x = 6
(\(\dfrac{5}{6}\) + \(\dfrac{7}{x}\)) - \(\dfrac{16}{12}\) = \(\dfrac{2}{3}\)
\(\dfrac{5}{6}\) + \(\dfrac{7}{x}\) = \(\dfrac{2}{3}\) + \(\dfrac{16}{12}\)
\(\dfrac{5}{6}\) + \(\dfrac{7}{x}\) = 2
\(\dfrac{7}{x}\) = 2 - \(\dfrac{5}{6}\)
\(\dfrac{7}{x}\) = \(\dfrac{1}{6}\)
\(x\) = 6 x (7 : 1)
\(x\) = 6 x 7
\(x\) = 42
#Yu
⇒56+7x=23+1612=812+1612=2412=2⇒56+7x=23+1612=812+1612=2412=2