\(-5\left(4x-1\right)\left(x-2\right)=2\left(4x-1\right)^2\\ =>-5\left(4x-1\right)\left(x-2\right)-2\left(4x-1\right)^2=0\\ =>\left(4x-1\right)\left[-5\left(x-2\right)-2\left(4x-1\right)\right]=0\\ =>\left(4x-1\right)\left(-5x+10-8x+2\right)=0\\ =>\left(4x-1\right)\left(-13x+12\right)=0\\ =>\left[{}\begin{matrix}4x-1=0\\-13x+12=0\end{matrix}\right.=>\left[{}\begin{matrix}x=\dfrac{1}{4}\\x=\dfrac{12}{13}\end{matrix}\right.\)
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