Question

4x²(x-3)+9(3-x)

Answer 1

\(4x^2\left(x-3\right)+9\left(3-x\right)=4x^2\left(x-3\right)-9\left(x-3\right)\)

\(=\left(4x^2-9\right)\left(x-3\right)=\left(2x-3\right)\left(2x+3\right)\left(x-3\right)\)

Answer 2

4x²(x-3)+9(3-x)=0

⇒4x²(x-3)-9(x-3)=0

⇒(4x²-9)(x-3)=0

hoặc 4x²-9=0⇒x=1,5

hoặc x-3=0⇒x=3