Question

\(4^x\)+\(2^{2x+1}\)=48

Answer 1

`4^x + 2^(2x+1) = 48`

`=> 2^(2x) + 2^(2x) xx 2 = 48`

`=> 2^(2x) xx3 = 48`

`=> 2^2x = 48  :3`

`=> 2^2x = 16`

`=> 4^x = 16`

`=> 4^x = 4^2`

`=> x = 2`

Vậy `x=2`

Answer 2

 4^x + 2^2x+1 = 48 

 2^x + 2^2x+1 = 48

  2^2x . (2 + 1 ) = 48

  2^2x . 3 = 48

  2^2x = 48 : 3 

  2^2x = 16

  2^2x = 2⁴

  2x = 4

   x = 4 : 2 

   x = 2 

Vậy x = 2