\(4x-\left(2x+1\right)=\dfrac{3}{4-2x}\)đk x khác 2
\(\Rightarrow4x\left(4-2x\right)-\left(2x+1\right)\left(4-2x\right)=3\)
\(\Leftrightarrow16x-8x^2-\left(8x-4x^2+4-2x\right)=3\Leftrightarrow-4x^2+10x-7=0\Leftrightarrow x=\dfrac{-5\pm\sqrt{53}}{4}\)