Question

cho đa thức P(x)=x^4+2x^2+1;Q(x)=x^4+4x^3+2x^2-4x+1 tính P(-1);P(1/2);Q(-2);Q(1)

 

 

Answer 1

\(P\left(-1\right)=\left(-1\right)^4+2\cdot\left(-1\right)^2+1=1+2+1=4\)

\(P\left(\dfrac{1}{2}\right)=\left(\dfrac{1}{2}\right)^4+2\cdot\left(\dfrac{1}{2}\right)^2+1=\dfrac{1}{16}+\dfrac{1}{2}+1=\dfrac{9}{16}\)

Answer 2

\(Q\left(-2\right)=\left(-2\right)^4+4\cdot\left(-2\right)^3+2\cdot\left(-2\right)^2-4\cdot\left(-2\right)+1=16-32+8+8+1=1\)

Answer 3

\(Q\left(1\right)=1^4+4\cdot1^3+2\cdot1^2-4\cdot1+1=1+4+2-4+1=5+3-4=2-4=-2\)