`46 - 2(x-1)^2 = 14`
`=> 2(x-1)^2 = 46 - 14`
`=> 2(x-1)^2 = 32`
`=> (x-1)^2 = 16`
`=> (x-1)^2 = (+-4)^2`
`=> x - 1 = 4` hoặc `x-1=-4`
`=> x=5` hoặc `x=-3`
Vậy: `x=5 ; x=-3`
\(46-2\cdot\left(x-1\right)^2=14\\ 2\cdot\left(x-1\right)^2=32\\ \left(x-1\right)^2=16\\ \left(x-1\right)^2=\left(\pm4\right)^2\\ x-1=\pm4\\ Th1:x-1=4=>x=5\\ Th2:x-1=-4=>x=-3\)