\(\Leftrightarrow\dfrac{4}{5}x-\dfrac{1}{3}x+\dfrac{2}{5}+1=\dfrac{1}{3}\\ \Leftrightarrow\dfrac{7}{15}x=-\dfrac{16}{15}\\ \Leftrightarrow x=-\dfrac{16}{7}\)
`4/5x - 2/3 . (1/2x - 3/5)+1=1/3`
`4/5x - 2/3 . 1/2x +(-2/3 . (-3/5))+1=1/3`
`4/5 x - 1/3x + 2/5+1=1/3`
`(4/5x-1/3x)+2/5+1=1/3`
`[(4/5-1/3)x]+2/5+1=1/3`
`7/15x +2/5 +1=1/3`
`7/15x+2/5+5/5 = 1/3`
`7/15 x + 7/5 = 1/3`
`7/15 x = 1/3 - 7/5`
`7/15 x = 5/15 - 21/15`
`7/15x = -16/15`
`x=-16/15:7/15`
`x=-16/15xx 15/7`
`x=-16/7`
Vậy `x=-16/7`