\(\frac{450}{x+5}+1=\frac{450}{x}\)
\(\Leftrightarrow\frac{450x}{x\left(x+5\right)}+\frac{x\left(x+5\right)}{x\left(x+5\right)}=\frac{450\left(x+5\right)}{x\left(x+5\right)}\)
Khử mẫu : \(\Leftrightarrow450x+x^2+5x=450x+2250\)
\(\Leftrightarrow455x+x^2-450x-2250=0\)
\(\Leftrightarrow x^2-5x-2250=0\)delta nốt hộ