Question

4(3x-2)+(2-3x)^3

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Answer 1

\(4\left(3x-2\right)+\left(2-3x\right)^3\)

\(=\left(2-3x\right)^3-4\left(2-3x\right)\)

\(=\left(2-3x\right)\left[\left(2-3x\right)^2-4\right]\)

\(=\left(-3x+2\right)\left(-3x+2-2\right)\left(-3x+2+2\right)\)

\(=-3x\cdot\left(-3x+2\right)\left(-3x+4\right)\)