Question

\(4.3^3-[3^2.x+2(4^2-15)]=10^2-12\)

Answer 1

\(4.27-\left[9.x+2\left(16-15\right)\right]=100-12\\ 4.27-\left[9.x+2\right]=88\\ 4.27-9.x-2=88\\ 4.27-9.x=88+2\\ 4.27-9.x=90\\ 108-9.x=90\\ 9.x=108-90\\ 9.x=18\\ x=18:9=2\)

Answer 2

\(4.3^3-\left[3^2x+2\left(4^2-15\right)\right]=10^2-12.\)

\(\Leftrightarrow108-\left(9x+32-30\right)=88.\)

\(\Leftrightarrow9x+2=20.\)

\(\Leftrightarrow x=2.\)

Vậy x = 2 là nghiệm của phương trình.

Answer 3