`@` `\text {Ans}`
`\downarrow`
\(\left(-3\right)^x\div81=-27\)
`=>`\(\left(-3\right)^x=-27\cdot81\)
`=>`\(\left(-3\right)^x=\left(-3\right)^3\cdot3^4\)
`=>`\(\left(-3\right)^x=\left(-3\right)^7\)
`=> x=7`
Vậy, `x=7.`
`@` `\text {Kaizuu lv u}`
(-3)x . 81 = -27
<=> (-3)x . (-3)4 = (-3)3
<=> (-3)x+4 = (-3)3
=> x+4=3
<=>x= -1