\(3.x^2=48\)
\(x^2=48:3\)
\(x^2=16\)
\(x^2=4^2\)
\(\Rightarrow x=4\)
\(3.x^2=48\)
\(x^2=48:3=16\)
\(x^2=16=4^2\)
\(^{=>x=4}\)
Nhớ đúng cho mk nha bn ^^
\(3\cdot x^2=48\)
\(\Leftrightarrow x^2=48:3\)
\(\Leftrightarrow x^2=12\)
\(\Leftrightarrow x^2=\left(\pm\sqrt{12}\right)^2\Leftrightarrow x=\pm\sqrt{12}\)
\(3.x^2=48\)
\(x^2=48:3\)
\(x^2=16\)
\(x^2=4^2\)
\(\Rightarrow x=4\)
\(3\cdot x^2=48\)
\(x^2=48:3\)
\(x^2=16\)
mà 42 = 16 và ( - 4 )2 = 16
=> \(x\in\left\{4;-4\right\}\)
Vậy...
Cbht
\(3x^2=48\)
\(\Leftrightarrow x^2=48:3\)
\(\Leftrightarrow x^2=16\)
\(\Leftrightarrow x^2=4^2=\left(-4\right)^2\)
\(\Leftrightarrow\orbr{\begin{cases}x=4\\x=-4\end{cases}}\)
\(3.x^2=48\)
\(x^2=48:3\)
\(x^2=16\)
\(\Rightarrow x^2=4^2\)hoặc \(x^2=\left(-4\right)^2\)
\(\Rightarrow x=4\)hoặc \(x=-4\)
Vậy \(x\in\left\{4;-4\right\}\)
Mk nhầm!
\(3\times x^2=48\)
\(\Leftrightarrow x^2=48:3\)
\(\Leftrightarrow x^2=16\)
\(\Leftrightarrow x^2=\left(\pm4\right)^2\Leftrightarrow x=\pm4\)
3.x2=48
x2=48:3
x2=16
\(\Rightarrow\) x2 =42=(-4)2
\(\Rightarrow\)TH1:x=4 TH2:x=-4
Vậy x =4 hoặc x=-4