Question

-3x^2 + 16x - 297 = 0

Answer 1

\(\text{Δ}=16^2-4\cdot\left(-3\right)\cdot\left(-297\right)=-3308< 0\)

Do đó: PTVN

Answer 2

`-> -3(x^2 + 16/3 + 99) = 0`.

`-> -3(x^2 + 2 . 8/3 + 64/9 + 827/9) =0`

`-> -3(x-8/3)^2 - 827/3 = 0`.

Vì `-3(x-8/3)^2 <=0 => -3(x-8/3)^2 - 827/3 <= -827/3 < 0`.

`=> x = cancel O`.