Question

(3x-2)^2 - (x+6)^2 =0

Answer 1

`(3x-2)^2 - (x+6)^2 =0`

`<=> (3x - 2 + x + 6)(3x - 2 - x - 6) = 0`

`<=> (4x + 4)(2x - 8) = 0`

`<=> 4(x+1) . 2(x - 4) = 0`

`<=> (x+1)(x-4) = 0`

`<=> x = -1 ` hoặc `x = 4`

Vậy ...

Answer 2

\(\left(3x-2\right)^2-\left(x+6\right)^2=0\)

=>(3x-2-x-6)(3x-2+x+6)=0

=>(2x-8)(4x+4)=0

=>\(\left[{}\begin{matrix}2x-8=0\\4x+4=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=4\\x=-1\end{matrix}\right.\)