Ta có: \(\left(3x-1.5\right)\left(\dfrac{-1}{2}x+5\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}3x-1.5=0\\\dfrac{-1}{2}x+5=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}3x=1.5\\\dfrac{-1}{2}x=-5\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{2}\\x=10\end{matrix}\right.\)
Vậy: \(x\in\left\{\dfrac{1}{2};10\right\}\)
Giải:
(3.x-1.5).(-1/2.x+5)=0
=> 3x-1.5=0 hoặc -1/2x+5=0
x=1/2 hoặc x=10
Vậy x ∈{1/2;10}
Chúc bạn học tốt!