\(\dfrac{3}{5}x+\left(x+0,5\right)=-\dfrac{13}{15}\)
=>\(\dfrac{3}{5}x+x+0,5=-\dfrac{13}{15}\)
=>\(\dfrac{4}{5}x=-\dfrac{13}{15}-\dfrac{1}{2}=-\dfrac{26}{30}-\dfrac{15}{30}=-\dfrac{41}{30}\)
=>\(x=-\dfrac{41}{30}:\dfrac{4}{5}=-\dfrac{41}{30}\cdot\dfrac{5}{4}=\dfrac{-41}{6\cdot4}=-\dfrac{41}{24}\)
tìm x,biết 5x-4/5=x+13/15
Tìm x biết|11-x|+|13-x|+|15-x|+|17-x|+5x+4=0
1) 1/3 - 5/6 + 3/2 2) 2/13 - ( 15/13 +4 - 0,5 ) 3) -( 1/9 +7/5 - 3/11) + ( -2/5 + 17/9 - 8/11 ) 4) 5,75 - 3,25 +5 5/6
| x -0,5 |-1/3 = 1/4
5x=4y và 2x-3y=14
Tìm x:
A) |0,5-3x|=3x-0,5
B) |5x-10|+|0,2-0,1x=1
C) |x+2|-|x+7|=0
D) |x-1|+|x-4|=3
Tìm x
a) 6x(5x + 3) + 3x(1 – 10x) = 7 b) (3x – 3)(5 – 21x) + (7x + 4)(9x – 5) = 44
c) (x + 1)(x + 2)(x + 5) – x2(x + 8) = 27
d) 5x(12x + 7) – 3x(20x – 5) = - 100
e) 0,6x(x – 0,5) – 0,3x(2x + 1,3) = 0,138
\(\left(\dfrac{1}{3}+\dfrac{12}{67}+\dfrac{13}{41}\right)-\left(\dfrac{79}{67}-\dfrac{28}{41}\right)\)
\(\left(\dfrac{15}{4}-5x\right)\cdot\left(9x^2-4\right)=0\)
\(\sqrt{x-2}+\dfrac{1}{3}=1\)
Tìm x:\(a,\frac{6x-5}{-7}=\frac{5x-3}{-5}\\ b,\frac{12-7x}{-13}=\frac{4-3x}{-5}\\ c,\frac{2x+4}{7}=\frac{4x-2}{15}\)
M(x)=x⁴+5x³-x²+x-0,5 N(x)=3x⁴-5x²-x-2,5 Hãy tính M(x)+N(x) và M(x)-N(x)
Tim X
a/|X+2| - |X+7|=0
b/|2X-1| = 2X-1
c/| 0,5-3X | = 3X-0,5
d/| 5X+1| - 10X = 0,5
