\(\left|x-0,5\right|-\dfrac{1}{3}=\dfrac{1}{4}\\ \Rightarrow\left|x-\dfrac{1}{2}\right|=\dfrac{7}{12}\\ \Rightarrow\left[{}\begin{matrix}x-\dfrac{1}{2}=\dfrac{7}{12}\\\dfrac{1}{2}-x=\dfrac{7}{12}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{13}{12}\\x=-\dfrac{1}{12}\end{matrix}\right.\\ 5x=4y\Rightarrow\dfrac{x}{4}=\dfrac{y}{5}=\dfrac{2x}{8}=\dfrac{3y}{15}=\dfrac{2x-3y}{8-15}=\dfrac{14}{-7}=-2\\ \Rightarrow\left\{{}\begin{matrix}x=-8\\y=-10\end{matrix}\right.\)