\(3^3-\left(x+2^4\right)=7\)
\(\Rightarrow27-\left(x+16\right)=7\)
\(\Rightarrow x+16=27-7\)
\(\Rightarrow x+16=20\)
\(\Rightarrow x=20-16\)
\(\Rightarrow x=4\)
Vậy x=4
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\(3^3-\left(x+2^4\right)=7\)
\(27-\left(x+16\right)=7\)
\(x+16=27-7\)
\(x+16=20\)
\(x=20-16\)
\(x=4\)
\(#WendyDang\)
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