-32-(x-5)=0
=>x-5=-32-0=-32
=>x=(-32)+5
=>x=-27
-32 - (x - 5) = 0
x - 5 = -32 - 0
x - 5 = -32
x = -32 - 5
x = -27
-32-(x-5)=0
(x-5)=(-32)-0
(x-5)=-32
x=-32+5
x=-27
-32-(x-5)=0
=>x-5=-32-0=-32
=>x=(-32)+5
=>x=-27
-32 - (x - 5) = 0
x - 5 = -32 - 0
x - 5 = -32
x = -32 - 5
x = -27
-32-(x-5)=0
(x-5)=(-32)-0
(x-5)=-32
x=-32+5
x=-27
(x –15) .15 = 0 b) 32 (x –10 ) = 32
c) ( x – 5)(x – 7) = 0 d) (x – 35).35 = 35
Tìm x eN biết
a) (x –15) .15 = 0 b) 32 (x –10 ) = 32 c/ ( x – 5)(x – 7) = 0 d/ (x – 35).35 = 3
a, 32 . ( x - 10) = 32
b, ( x - 105 ) : 21 = 15
c, ( x - 5 ) . ( x - 7 ) = 0
5-(10-x)=7
-32-(x-5)=0
(-32)-(x-5)=0
BÀI 4 . TÌM x
1 . X + 5 . 2 - { 32 + 16 . 3 : 6 } = 0
2 . { X -1 }^ 5 = 32
3 . { 2X - 3 }^ 2 = 25
tìm x
((x-2)^2-49).((x+1).5-32)=0
Tìm x, biết:
a) (x- 5.9).2 = 0;
b) 21. (32 - x) = 21;
c) 25.(2.x - 4).12 = 0;
d) (x- 4) : 6 - 5 = 10.
1) –45 + 5.(–2x) = 95
2) x.(12 + x).(71 – x) = 0
3) (x – 11).(x + 12).(–x – 13) = 0
4) |2.x – 15| = 7
5) –2.|x + 32| = –112