\(=\dfrac{3}{10}-\dfrac{2}{3}.3=\dfrac{3}{10}-2=\dfrac{3}{10}-\dfrac{20}{10}=-\dfrac{17}{10}\)
\(\dfrac{3}{10}-\left(\dfrac{1}{6}+\dfrac{1}{2}\right):\dfrac{1}{3}=\dfrac{3}{10}-\left(\dfrac{1+3}{6}\right):\dfrac{1}{3}=\dfrac{3}{10}-\dfrac{4}{6}:\dfrac{1}{3}=\dfrac{3}{10}-2=\dfrac{3-20}{10}=-\dfrac{17}{10}\)