PTHH: \(KOH+HCl\rightarrow KCl+H_2O\)
Ta có: \(m_{HCl}=150\cdot14,6\%=21,9\left(g\right)\) \(\Rightarrow n_{HCl}=\dfrac{21,9}{36,5}=0,6\left(mol\right)=n_{KOH}=n_{KCl}\)
\(\Rightarrow\left\{{}\begin{matrix}V_{KOH}=\dfrac{0,6}{1}=0,6\left(l\right)=600\left(ml\right)\\m_{KCl}=0,6\cdot74,5=44,7\left(g\right)\end{matrix}\right.\)