Question

3 /2x5 + 3/5x8 +3/8x11 +  ...   + 3/ 299x302

Answer 1

\(\dfrac{3}{2.5}+\dfrac{3}{5.8}+...+\dfrac{3}{299.302}\)

\(=\dfrac{1}{2}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{8}+...+\dfrac{1}{299}-\dfrac{1}{302}\)

\(=\dfrac{1}{2}-\dfrac{1}{302}\)

\(=\dfrac{150}{302}=\dfrac{75}{151}\)

Answer 2

`3/(2xx5)+3/(5xx8)+3/(8xx11)+...+3/(299xx302)`

`=1/2-1/5+1/5-1/8+1/8-1/11+...+1/299-1/302`

`=1/2-1/302`

`=151/302-1/302`

`=150/302`

`=75/151`