\(\dfrac{3-2}{6-5}=\dfrac{3-2\left(x+7\right)}{4}\)
Đề là như này đúng hăm
\(3-\dfrac{2}{6}-5=3-\dfrac{2\left(x+7\right)}{4}\\ =>-\dfrac{7}{3}=3-\dfrac{2x+14}{4}\\ =>-\dfrac{7}{3}=\dfrac{12}{4}-\dfrac{2x+14}{4}\\ =>-\dfrac{7}{3}=\dfrac{12-2x-4}{4}\\ =>-\dfrac{7}{3}=\dfrac{8-2x}{4}\\ ...\\ x=8,666666667\)