\(\Leftrightarrow2x\left(2x-1\right)-4x\left(x+3\right)=0\)
\(\Leftrightarrow4x^2-2x-4x^2-12x=0\)
=>-14x=0
hay x=0(nhận)
ĐKXĐ:\(\left\{{}\begin{matrix}x\ne-3\\x\ne\dfrac{1}{2}\end{matrix}\right.\)
\(\dfrac{2x}{x+3}-\dfrac{4x}{2x-1}=0\\ \Leftrightarrow\dfrac{2x\left(2x-1\right)-4x\left(x+3\right)}{\left(x+3\right)\left(2x-1\right)}=0\\ \Leftrightarrow\dfrac{4x^2-2x-4x^2-12x}{\left(x+3\right)\left(2x-1\right)}=0\\ \Rightarrow-14x=0\\ \Leftrightarrow x=0\left(tm\right)\)
⇔2x(2x−1)−4x(x+3)=0⇔2x(2x−1)−4x(x+3)=0
⇔4x2−2x−4x2−12x=0⇔4x2−2x−4x2−12x=0
=>-14x=0
hay x=0(nhận)
