Question

( 2x+3)^2 + 2=27

Answer 1

\(\left(2x+3\right)^2+2=27\)

\(=\left(2x+3\right)^2=27-2=25=5^2\)

\(=\left[{}\begin{matrix}2x+3=5\\2x+3=-5\end{matrix}\right.=\left[{}\begin{matrix}2x=5-3=2\\2x=\left(-5\right)-3=-8\end{matrix}\right.\) ⇒\(\left[{}\begin{matrix}x=1\\x=-4\end{matrix}\right.\)

Answer 2

=>(2x+3)²=25

=>2x+3=5 hoặc 2x+3=-5

=>2x=2 hoặc 2x=-8

=>x=1 hoặc x=-4

Answer 3

<=> (2x + 3)² = 25

<=> (2x + 3)² = 5²

<=> 2x + 3 = 5 hoặc -5

=> 2x + 3 = 5

<=> 2x = 2 <=> x = 1

=> 2x + 3 = -5

<=> 2x = -8 <=> x = -4

Vậy ..