2x^2 + 5x + 3 = 0
=> 2x^2 + 2x + 3x + 3 = 0
=> 2x(x+1)+ 3(x+1) = 0
=> (2x+3)(x+1)=0
=> 2x+3 = 0 hoặc x+1 = 0
=> x= -3/2 hoặc x= -1
2x2+5x+3=0
<=>2x2+2x+3x+3=0
<=>2x.(x+1)+3.(x+1)=0
<=>(2x+3).(x+1)=0
<=>\(\orbr{\begin{cases}2x+3=0\\x+1=0\end{cases}}< =>\orbr{\begin{cases}2x=-3=>x=-1,5\\x=-1\end{cases}}\)