Question

2^x+1+5×2^x+2=176

Bài này e ko lm đc

Ai giúp e với ak

Answer 1

\(2^{x+1}+5\cdot2^{x+2}=176\)

\(\Rightarrow2^{x+1}+5\cdot2\cdot2^{x+1}=176\)

\(\Rightarrow2^{x+1}\cdot\left(1+5\cdot2\right)=176\)

\(\Rightarrow2^{x+1}\cdot11=176\)

\(\Rightarrow2^{x+1}=176:11\)

\(\Rightarrow2^{x+1}=16\)

\(\Rightarrow2^{x+1}=2^4\)

\(\Rightarrow x+1=4\)

\(\Rightarrow x=4-1=3\)

Answer 2

\(2^{x+1}+5\cdot2^{x+2}=176\)
\(\Rightarrow2^x\cdot2+5\cdot2^x\cdot2^2=176\)
\(\Rightarrow2^x\cdot2+2^x\cdot20=176\)
\(\Rightarrow2^x\left(2+20\right)=176\)
\(\Rightarrow2^x\cdot22=176\)
\(\Rightarrow2^x=8\)
\(\Rightarrow x=3\)