Tìm x thuộc Z biết :
a, 4x - 2x + x -27 : 9 = 33
b,| 5 - 2x | - |6 - 9| . 5 -2x =3
tìm x biết:
(3x-1) [- 1/2x+5]=0
1/4+1/3:(2x-1)=-5
[2x+3/5]2 - 9/25=0
-5(x+1/5)-1/2(x-2/3)=3/2x - 5 /6
[x+1/2]x [2/3-2x]=0
17/2-|2x-3/4|=-7/4
2/3x-1/2x =5/12
(x+1/5)2+17/25=26/25
[x.44/7+3/7].11/5-3/7=-2
3[3x-1/2]+1/9=0
Bài 1:
a)-2x-3.( x-17 )= 34-2.( -x+25 )
b)17x+3.( -16x-37 )= 2x+43-4x
c){-3x+2. [ 45-x-3 ( 3x+7 ) -2x]+4x} = 55
g)-103-57: [ 5.( 2x-1 )2-( -9 )0 ]
Bài 2:
a)-5.( -x+7 )-3.( -x-5 )=-4.( 12-x )+48
b)7.( -x-7 )-4.( -2x-11 )=7.( 4x+10 )+9
c)-2.( 15-3x )-4.( -7x+8 )=-5-9.( -2x+1 )
d)5.( -3x-7 )-4.( -2x-11 )=7.( 4x+10 )+9
e)4( x-2 )2-13=( -3 )2.2-11.( -3 )
f)-52-( 2x-1 )3=( -13 ).( -3 )
\(\frac{2x}{9}+5=\frac{x}{3}\)<=> \(\frac{x}{3}-\frac{2x}{9}=5\)
<=> \(\frac{3x}{9}-\frac{2x}{9}=\frac{x}{9}=5\)
=> \(x=5.9=45\left(hs\right)\)
tìm x
a)5^2x . 5 = 3125
b)5^x 5^x+3 =630
c)3^2x + 1 = 243
d) 3^2x+1 = 9
Tìm x
a) 5^2x . 5 =3125
b)5^x + 5^x+3= 630
c)3^2x+1=243
d)3^2x+1=9
e) ( x + 3)^3 = ( 2x) ^3
f) ( 5 - x )^5 = 32
g) ( 5x - 6)^3 = 64
h)5 . 9^x = 405
i) 11^5 : 11^ n - 2 = 11^5
k) ( 3x)^3 = ( 2x + 1)^3
tính C=1/3*5+1/5*7+1/7*9+............+1/(2X+1)(2X+3)=15/93
tìm x biết1\3*5+1\5*7+1\7*9+....+1\(2x+1)(2x+3)